2x^2+22x+340=1292

Solution for 2x^2+22x+340=1292 equation:

2x^2+22x+340=1292

We move all terms to the left:

2x^2+22x+340-(1292)=0

We add all the numbers together, and all the variables

2x^2+22x-952=0

a = 2; b = 22; c = -952;
Δ = b2-4ac
Δ = 222-4·2·(-952)
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8100}=90$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-90}{2*2}=\frac{-112}{4}
=-28
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+90}{2*2}=\frac{68}{4}
=17
$